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Question

For perfectly reflecting mirror, the force exerted by the light of power $P$ is

$\mathrm{F}=\frac{2(	ext { power })}{\mathrm{c}}$

for equilibri

Vedclass · Accepted Answer

$100$

Vedclass · Answer

For perfectly reflecting mirror, the force exerted by the light of power $P$ is

$\mathrm{F}=\frac{2(	ext { power })}{\mathrm{c}}$

for equilibrium

$\mathrm{F}=\mathrm{mg}=\frac{2(	ext { power })}{\mathrm{c}}$

Power $ = \frac{{mg 	imes c}}{2} = 30 	imes {10^6}{m{\,W}}$

As only $30 \%$ of the power is given to the mirror

So, $\mathrm{P}^{\prime}=30 	imes \frac{100}{30}=100 \mathrm{\,MW}$

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